Any mathematically inclined who can compute the odds of a random serial number containing a "3"? I know it's way more than one in ten, because of the 30' and 300s and 3000s, but the logic form there on escapes me for the moment. Should the calculations be constrained to military guns?
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"... Liberty is the seed and soil, the air and light, the dew and rain of progress, love and joy."-- Robert Greene Ingersoll 1894
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